도전은 간단하다 :

단어를 생성하십시오.

명세서:

• 단어는 발음 할 수 있어야합니다.
  • 이것은 "자음과 모음 사이의 대체"로 정의됩니다.
  • 자음은 다음 문자 중 하나입니다. bcdfghjklmnpqrstvwxz
  • 모음은 다음 문자 중 하나입니다. aeiouy
• 단어는 무작위로 생성되어야합니다.
• 단어는 모든 자음과 모음을 포함 할 수 있어야합니다. ( bcdf자음과 aei모음 에만 사용할 수는 없습니다 .)
• 단어는 10 글자를 포함해야합니다.
• 가장 짧은 코드 (문자 수)가 이깁니다.

GolfScript, 32 자

['aeiouy'.123,97>^]5*{.,rand=}%+

그것을 실행 온라인 .

루비 : 56 자

([v=%w(a e i o u y),[*?a..?z]-v]*5).map{|a|$><<a.sample}

출력 예 :

• itopytojog
• 우마 푸 죠짐
• 이 파고다
• yfoqinifyw
• ebylipodiz

파이썬, 81

from random import*
print''.join(map(choice,["bcdfghjklmnpqrstvwxz","aeiouy"]*5))

그들을 발음하는 행운을 빕니다.

코볼, 255

그래서 나는 현재 COBOL을 배우고 있습니다. 이 질문을 연습으로 사용했습니다. 그것을 골프하려고했다.

선행 공백이 없으면 255이고 286 바이트입니다.

가치가있는 것은 VS2012의 Microfocus COBOL에서 실행되며 다른 곳에서 실행 될지 전혀 모릅니다.

       1 l pic 99 1 s pic x(26) value'aeiouybcdfghjklmnpqrstvwxz' 1 r
       pic 99 1 v pic 9 1 q pic 99. accept q perform test after varying
       l from 1 by 1 until l>9 compute v=function mod(l,2) compute r=1+
       function random(q*l)*5+v*15+v*5 display s(r:1)end-perform exit

APL (34)

,⍉↑(V[5?6])((⎕A~V←'AEIOUY')[5?20])

자바 스크립트, 74

for(a=b=[];a++-5;)b+="bcdfghjklmnpqrstvwxz"[c=new Date*a%20]+"aeiouy"[c%6]

모든 조합을 생성하지는 않지만 모든 자음과 모음이 나타납니다.

자바 스크립트, 79

for(a=b=[];a--+5;)b+="bcdfghjklmnpqrstvwxz"[c=Math.random()*20^0]+"aeiouy"[c%6]

더 "무작위"버전.

루비 : 70 66 자

10.times{|i|$><<["aeiouy"*4,"bcdfghjklmnpqrstvwxz"][i%2][rand 20]}

샘플 실행 :

bash-4.1$ ruby -e '10.times{|i|$><<["aeiouy"*4,"bcdfghjklmnpqrstvwxz"][i%2][rand 20]}'
izogoreroz

bash-4.1$ ruby -e '10.times{|i|$><<["aeiouy"*4,"bcdfghjklmnpqrstvwxz"][i%2][rand 20]}'
onewijolen

bash-4.1$ ruby -e '10.times{|i|$><<["aeiouy"*4,"bcdfghjklmnpqrstvwxz"][i%2][rand 20]}'
amilyfilil

R : 105 자

a=c(1,5,9,15,21,25)
l=letters
s=sample
cat(apply(cbind(s(l[-a],5),s(l[a],5)),1,paste,collapse=""),sep="")

J (51)

,|:>(<"1[5?6 20){&.>'aeiouy';'bcdfghjklmnpqrstvwxz'

가공, 100 99 93 87

int i=10;while(i-->0)"aeiouybcdfghjklmnpqrstvwxz".charAt((int)random(i%2*6,6+i%2*i*2));

질문을 면밀히 조사하면 출력이 필요하지 않습니다. 이에 따라 조정했습니다.

Objective-C, 129

main(){int i=10;while(i-->0)printf("%c",[(i%2==0)?@"aeiouy":@"bcdfghjklmnpqrstvwxz"characterAtIndex:arc4random()%(6+(i%2)*14)]);}

With the help of Daniero

(I love to use the tends to operator (-->)

Java AKA the most verbose language ever created, 176 with help of Doorknob, Daniero and Peter Taylor (thanks guys!)

class w{public static void main(String[]a){int i=11;while(--i>0)System.out.print((i%2==0?"aeiouy":"bcdfghjklmnpqrstvwxz").charAt(new java.util.Random().nextInt(6+(i%2)*14)));}}

Ungolfed:

    class w {

        public static void main(String[] a) {
            int i = 11;
            while (--i > 0) {
                System.out.print((i % 2 == 0 ? "aeiouy" : "bcdfghjklmnpqrstvwxz").charAt(new java.util.Random().nextInt(6 + (i % 2) * 14)));
            }
     }

}

Javascript, 85

for(r=Math.random,s="",i=5;i--;)s+="bcdfghjklmnpqrstvwxz"[20*r()|0]+"aeiouy"[6*r()|0]

If run from the console, output is shown. Explicit display would add alert(s) at 8 chars, still shorter than the other JS solutions.

Thanks C5H8NNaO4 and Howard!

Javascript, 135 122 96 86 characters

s='';c=5;r=Math.random;while(c--)s+='bcdfghjklmnpqrstvwxz'[r()*20|0]+'aeiouy'[r()*6|0]

PHP, 100 Characters

<?while($i<6){echo substr('bcdfghjklmnpqrstvwxz',rand(0,20),1).substr('aeiouy',rand(0,5),1);$i++;}?>

Unix tools: 73 bytes

And not guaranteed running time :)

</dev/urandom grep -ao '[aeiouy][bcdfghjklmnpqrstvwxz]'|head -5|paste -sd ''

Only problem is that the generated string will start with a "vowel" every time.

(edit: changed ' ' to '' in the args of paste) (another edit: removed -P from grep options, thanks to manatwork)

Pyth, 26 characters

J-G"aeiouy"VT=k+kOJ=J-GJ;k

You can try it in the online compiler here.

Someone posted a very similar challenge but it was closed after I had made a solution. I didn't realize it, but this question actually predates the creation of Pyth. Anyway, here is the breakdown:

J                             Set string J equal to:
  G                            the entire alphabet (lowercase, in order)
 - "aeiouy"                    minus the vowels
           VT                 For n in range(1, 10):
             =k                   Set string k to:
                k                  k (defaults to empty string)
               + OJ                plus a random character from J
                   =J             Set J to:
                      G            the entire alphabet
                     - J           minus J
                        ;     End of loop
                         k    print k

Every time the loop is run, J switches from being a list of consonants to a list of vowels. That way we can just pick a random letter from J each time.
There may be a way to initialize J in the loop or remove the explicit assignments from the loop, but I have not had success with either yet.

APL 30 26

,('EIOUY'∪⎕A)[6(|,+)⍪5?20]

Explanation is very similar to the past version below, just reordered a bit to golf the solution.

Note: ⎕IO is set to 0

('EIOUY'∪⎕A)[,6(|,(⍪+))5?20]

Explanation:

'EIOUY'∪⎕A    puts vowels in front of all letters.
5?20            for the indexes we start choosing 5 random numbers between 0 and 19
6(|,(⍪+))        then we sum 6 and the random numbers, convert to 5x1 matrix (⍪), add a column before this one containing 6 modulo the random numbers. 
                [[[ this one can be rewritten as: (6|n) , ⍪(6+n)  for easier understanding]]]
,6(|,(⍪+))5?20  the leading comma just converts the matrix to a vector, mixing the vowel and consonants indexes.

Tryapl.org

PHP 79 bytes

<?for($c=bcdfghjklmnpqrstvwxz,$v=aeiouy;5>$i++;)echo$c[rand()%20],$v[rand()%6];

Fairly concise.

C: 101

main(){int x=5;while(x-->0){putchar("bcdfghjklmnpqrstvwxyz"[rand()%21]);putchar("aeiou"[rand()%5]);}}

Javascript, 104 87

a="";for(e=10;e--;)a+=(b=e&1?"bcdfghjklmnpqrstvwxz":"aeiouy")[0|Math.random()*b.length]

golfed a whole lot of simple unnecessary stuff, still not nearly as nice as copys' one

Oh, and that one just opped up during golfing: "dydudelidu"

_{Now I tried one using the 2 characters at once approach. Turns out it's almost the same as copys' second one, so I can't count it, also at 79. a="";for(e=5;e--;)a+="bcdfghjklmnpqrstvwxz"[m=0|20*Math.random()]+"aeiouy"[m%6]}

Brachylog, 9 bytes

Ḍ;Ẉṣᵐzh₅c

Try it online!

Gives output as a list of letters through the output variable.

   ṣ         Randomly shuffle
 ;  ᵐ        both
Ḍ            the consonants without y
  Ẉ          and the vowels with y,
     z       zip them into pairs,
      h₅     take the first five pairs,
             and output
        c    their concatenation.

F#, 166 characters

open System;String.Join("",(Random(),"aeiouybcdfghjklmnpqrstvwxz")|>(fun(r,s)->[0..5]|>List.collect(fun t->[s.Substring(6+r.Next()%20,1);s.Substring(r.Next()%6,1)])))

K, 40 bytes

,/+5?/:("bcdfghjklmnpqrstvwxz";"aeiouy")

5?"abc" will generate 5 random letters from the given string.

5?/: will generate 5 random letters from each of the strings on the right, producing two lists.

+ transposes those two lists, giving us a list of tuples with one random character from the first list and then one from the second list.

,/ is "raze"- fuse together all those tuples in sequence.

K5 can do this in 33 bytes by building the alphabet more cleverly and then using "except" (^) to remove the vowels, but K5 is much too new to be legal in this question:

,/+5?/:((`c$97+!26)^v;v:"aeiouy")

R, 83 bytes

cat(outer((l<-letters)[a<-c(1,5,9,15,21,25)],l[-a],paste0)[sample(1:120,5)],sep="")

Generate all possible vowel-consonant sequences in a matrix, then randomly sample 5 of them, yielding a 10-letter word.

05AB1E, 10 bytes

5FžPΩ?žOΩ?

Try it online or output $n$ amount of random words.

Explanation:

Pretty straight-forward:

5F      # Loop 5 times:
  žP    #  Push string "bcdfghjklmnpqrstvwxz"
    Ω   #  Pop and push a random character from this string
     ?  #  Output it without newline
  žOΩ?  #  Do the same with string "aeiouy"

Jelly, 13 bytes

Øy,ØYẊ€Zs5ḢŒl

Explanation:

Øy,ØYẊ€Zs5ḢŒl
Øy,ØY         Makes a list of two lists of characters: [[list-of-vowels-with-y], [list-of-consonants-without-y]]
     Ẋ€       Shuffle €ach.
       Z      Zip those two lists together. [[random-vowel, random-consonant],...]
        s5    Split them into chunks of five (because each pair contains two letters, this splits them into chunks of 10 letters)
          Ḣ   Take the list of 5 pairs.
           Œl Make each of the characters in it lowercase
              Implicit concatenation and print.

Try it online!