PHP
777 자
이것은 끔찍한 시도이지만 허점을 이용했다고 비난 할 수 없으며 운이 좋은 숫자입니다. 팁에 대한 ProgramFOX 덕분입니다.
<?php $i=9212;$b = array('zero','one','two','three','four','five','six','seven','eight','nine');$t='teen';$c = array('ten','eleven','tweleve','thir'.$t,$b[4].$t,'fif'.$t,$b[6].$t,$b[7].$t,$b[8].$t,$b[9].$t);$d = array('','','twenty','thirty','fourty','fifty','sixty','seventy','eighty','ninety');$e='hundred';$f='thousand';$j=str_split($i);if (strlen($i)===1){$a=$b[$i];}elseif (strlen($i)===3){$k=1;$a=$b[$j[0]].' '.$e.' '.x($j,$k);}elseif (strlen($i)===4){$k=2;$a=$b[$j[0]].' '.$f.' '.$b[$j[1]].' '.$e.' '.x($j,$k);}elseif (substr($i, -2, 1)==='1'){$a=$c[$j[1]];}else{$a=$d[$j[0]].' '.$b[$j[1]];}$a = str_replace('zero hundred','',$a);echo $a;function x($j,$k){global $i, $b, $c, $d;if (substr($i, -2, 1)==='1'){return $c[$j[$k+1]];}else{return $d[$j[$k]].' '.$b[$j[$k+1]];}}
긴 손
<?php
// Input
$i=9212;
// 0-9
$b = array('zero','one','two','three','four','five','six','seven','eight','nine');
// 10-19 (Very tricky)
$t='teen';
$c = array('ten','eleven','tweleve','thir'.$t,$b[4].$t,'fif'.$t,$b[6].$t,$b[7].$t,$b[8].$t,$b[9].$t);
// Left digit of 20-99
$d = array('','','twenty','thirty','fourty','fifty','sixty','seventy','eighty','ninety');
// Hundreds
$e='hundred';
// Thousands
$f='thousand';
// Split input
$j=str_split($i);
// 1 digit inputs
if (strlen($i)===1){$a=$b[$i];}
// 3 digit input
elseif (strlen($i)===3){$k=1;$a=$b[$j[0]].' '.$e.' '.x($j,$k);}
// 4 digit input
elseif (strlen($i)===4){$k=2;$a=$b[$j[0]].' '.$f.' '.$b[$j[1]].' '.$e.' '.x($j,$k);}
// 10-19
elseif (substr($i, -2, 1)==='1'){$a=$c[$j[1]];}
// 20-99
else{$a=$d[$j[0]].' '.$b[$j[1]];}
// Fix for thousand numbers
$a = str_replace('zero hundred','',$a);
// Result
echo $a;
// Abstracted function last 2 digits for 3 and 4 digit numbers
function x($j,$k){
global $i, $b, $c, $d;
// 10-19
if (substr($i, -2, 1)==='1'){return $c[$j[$k+1]];}
// 20-99
else{return $d[$j[$k]].' '.$b[$j[$k+1]];}
}