파이썬, 1110 바이트
연산자 오버로딩은 악하지 않습니다.
from re import*
class V(str):
def __add__(s,r):return s[:-1]+chr(ord(s[-1])+r)
class S(str):
def __str__(s):return "'"+s+"'"if '"'in s else'"'+s+'"'
def __repr__(s):return str(s)
def __add__(s,r):s=str(s)[1:-1];return S('['+s+']'if type(r)==L else '"+"' if(s,r)==('','')else s+r)
class I(int):
def __add__(s,r):return type(r)(int(s)+int(r))if s!=r else V('DONE')
def __div__(s,r):return N if r==0 else int(s)/int(r)
def __pos__(s):return s+c*10
def __mul__(s,r):return V('NaN.'+'0'*13+'13')if r==1 else int(s)*int(r)
class L(list):
def __add__(s,r):return V(str(r==s[-1]+1).upper())
def RANGE(a,b=0):return 2*(a,S(chr(ord(a)+1)))if b==0 else tuple([a]+[b-1,a+2]*((b-a)/4)+[b-1,b])
def FLOOR(n):return V('|\n|\n|\n|___%s___'%n)
def colorsrgb(c):
m={'blue':V('#0000FF')}
return m.get(c,N)
def colorssort():return V('rainbow')
N=V('NaN')
c=1
while True:
try:l=raw_input('[%d] >'%c)
except:break
l=sub(r'(?<!"|\.)(\d+)(?!\.|\d)',r'I(\1)',l)
l=sub(r'"(.*?)"',r'S("\1")',l)
l=sub(r'\[(.*?)\]',r'L([\1])',l)
l=sub(r'/\(','*(',l)
l=sub('s\.','s',l)
for x in str(eval(l)).split('\n'):print ' =',x
c+=1
내 목표는 가능한 한 일반적인 것으로 만드는 것만 큼 (당연히) 승리하지 못했습니다. 하드 코딩이 거의 없습니다. 같은 물건을 시도 RANGE(10), 9*1그리고 RANGE("A"), (2/0)+14그리고 "123"재미있는 결과!
샘플 세션은 다음과 같습니다.
ryan@DevPC-LX:~/golf/xktp$ python xktp.py
[1] >ryan@DevPC-LX:~/golf/xktp$ python xktp.py
[1] >1+1
= DONE
[2] >2+"2"
= "4"
[3] >"2"+2
Traceback (most recent call last):
File "xktp.py", line 31, in <module>
for x in str(eval(l)).split('\n'):print ' =',x
File "<string>", line 1, in <module>
File "xktp.py", line 7, in __add__
def __add__(s,r):s=str(s)[1:-1];return S('['+s+']'if type(r)==L else '"+"' if(s,r)==('','')else s+r)
TypeError: cannot concatenate 'str' and 'I' objects
ryan@DevPC-LX:~/golf/xktp$ python xktp.py
[1] >ryan@DevPC-LX:~/golf/xktp$
ryan@DevPC-LX:~/golf/xktp$
ryan@DevPC-LX:~/golf/xktp$
ryan@DevPC-LX:~/golf/xktp$ python xktp.py
[1] >2+"2"
= "4"
[2] >"2"+[]
= "[2]"
[3] >"2"+[1, 2, 3]
= "[2]"
[4] >(2/0)
= NaN
[5] >(2/0)+2
= NaP
[6] >(2/0)+14
= Na\
[7] >""+""
= '"+"'
[8] >[1,2,3]+2
= FALSE
[9] >[1,2,3]+4
= TRUE
[10] >[1,2,3,4,5,6,7]+9
= FALSE
[11] >[1,2,3,4,5,6,7]+8
= TRUE
[12] >2/(2-(3/2+1/2))
= NaN.000000000000013
[13] >9*1
= NaN.000000000000013
[14] >RANGE(" ")
= (" ", "!", " ", "!")
[15] >RANGE("2")
= ("2", "3", "2", "3")
[16] >RANGE(2)
Traceback (most recent call last):
File "xktp.py", line 31, in <module>
for x in str(eval(l)).split('\n'):print ' =',x
File "<string>", line 1, in <module>
File "xktp.py", line 15, in RANGE
def RANGE(a,b=0):return 2*(a,S(chr(ord(a)+1)))if b==0 else tuple([a]+[b-1,a+2]*((b-a)/4)+[b-1,b])
TypeError: ord() expected string of length 1, but I found
ryan@DevPC-LX:~/golf/xktp$ python xktp.py
[1] >ryan@DevPC-LX:~/golf/xktp$ # oops
ryan@DevPC-LX:~/golf/xktp$ python xktp.py
[1] >RANGE("2")
= ("2", "3", "2", "3")
[2] >RANGE(2*1)
Traceback (most recent call last):
File "xktp.py", line 31, in <module>
for x in str(eval(l)).split('\n'):print ' =',x
File "<string>", line 1, in <module>
File "xktp.py", line 15, in RANGE
def RANGE(a,b=0):return 2*(a,S(chr(ord(a)+1)))if b==0 else tuple([a]+[b-1,a+2]*((b-a)/4)+[b-1,b])
TypeError: ord() expected a character, but string of length 19 found
ryan@DevPC-LX:~/golf/xktp$ python xktp.py # oops again
[1] >RANGE(1,20)
= (1, 19, 3, 19, 3, 19, 3, 19, 3, 19, 20)
[2] >RANGE(1,5)
= (1, 4, 3, 4, 5)
[3] >RANGE(10,20)
= (10, 19, 12, 19, 12, 19, 20)
[4] >RANGE(10,200)
= (10, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 12, 199, 200)
[5] >+2
= 52
[6] >+"99"
Traceback (most recent call last):
File "xktp.py", line 31, in <module>
for x in str(eval(l)).split('\n'):print ' =',x
File "<string>", line 1, in <module>
TypeError: bad operand type for unary +: 'S'
ryan@DevPC-LX:~/golf/xktp$ python xktp.py # oops again and again!
[1] >FLOOR(200)
= |
= |
= |
= |___200___
[2] >2+2
= DONE
[3] >3+#
Traceback (most recent call last):
File "xktp.py", line 31, in <module>
for x in str(eval(l)).split('\n'):print ' =',x
File "<string>", line 1
I(3)+#
^
SyntaxError: unexpected EOF while parsing
ryan@DevPC-LX:~/golf/xktp$ python xktp.py
[1] >3+3
= DONE
[2] >ryan@DevPC-LX:~/golf/xktp$
10.5합니까, 아니면 전달 될 것이라고 가정 할 수 있습니까?