자바 스크립트 ES6, 905 바이트
Whew .. 12 시간제 시계가 짧지 않은 해결책을 죽였습니다 .
아스키 아트 898자를 인쇄하기위한 905 바이트
_=>(a=(d=Date)(c=new d(),z=O=>Math.abs(new d(a[3]+O)-c)).split` `)[1]=='Apr'&a[2]==20|~a[4].search(/(04|16):20/)?'0,0,2ca2o,0,10e,0,0,1eu9z4,0,22w,1ulajuo,0,bklxc,2zgg,i,120gdfk,8lc,1s1s,15,j0jf9c,7em8,tac,10,190zcw0,tm8w,ksk,hra0ia,mihog0,3aels,wy,iv8e15,b98u80,cvs1s,575,9fm71g,190zcw0,bg7vgg,1t4,148d4lu,121pblx,b9ea68,2b36,iv8hn5,9zleso,15kytz4,98cp,4fwpwk,zir9ud,1h9u3ln,11c6vb4,84kda8,kbuo05,b98u84,14possy,k9su6i,a26hwk,zvft34,kavrpc,1tn1j4,1r3jis,kamgao,a5bhq8,2b2q,beyt6x,j0y810,muhiww,9xl,a5b7s8,14npcwi,1bkfw1s,4ys,14lipw4,kalr6k,0,1aq,kalqzg,0,48m,2j6hqf,zik0zk,0,33mcjk,0,5'.split`,`.map(a=>('0'.repeat(32)+parseInt(a,36).toString(2)).substr(-32)).join``.match(/.{1,3}/g).map(a=>` .:\`|;'
`[parseInt(a,2)]).join``:~~((T=Math.min(z('/4/20'),z(` ${a[1]} ${++a[2]} 0:4:20`),z(' 4:20'),z(' 0:4:20'),z(' 16:20'),z(' 0:16:20'))/1000)/60)+` minutes and ${~~(T%60)} seconds left until your next hit.`
Ungolfed 코드
참고 : ungolfed 코드는 실행되지 않습니다
function() {
// (all vars here are actually global)
var d = Date; // short reference to Date object
var dateString = Date() // "Tue Apr 12 2016 20:13:00 GMT+0200 (W. Europe Daylight Time)"
.split` `; // ["Tue", "Apr", "12", ...]
var currentDate = new Date();
dateDiff = function(toAppend) {
return Math.abs( // no dates in the past
new Date(dateString[3] + toAppend) // new Date('2016' + something)
- currentDate // substract the current date.
// Thanks JS for the datetime implementation
);
}
if ((dateString[1] == 'Apr' & dateString[2] == 20) |
~dateString[4].search(/(04|16):20/)) { // if the time doesn't contain 04:20 or
// 16:20, this will return -1. ~-1 is 0
// and thus falsy
alert(printAscii());
} else {
alert(printTimeLeft());
}
}
function printAscii() {
var magicString = '0,0,2ca2o,0,10e,0,0,1eu9z4,0,22w,1ulajuo,0,bklxc,2zgg,i,120gdfk,8lc,1s1s,15,j0jf9c,7em8,tac,10,190zcw0,tm8w,ksk,hra0ia,mihog0,3aels,wy,iv8e15,b98u80,cvs1s,575,9fm71g,190zcw0,bg7vgg,1t4,148d4lu,121pblx,b9ea68,2b36,iv8hn5,9zleso,15kytz4,98cp,4fwpwk,zir9ud,1h9u3ln,11c6vb4,84kda8,kbuo05,b98u84,14possy,k9su6i,a26hwk,zvft34,kavrpc,1tn1j4,1r3jis,kamgao,a5bhq8,2b2q,beyt6x,j0y810,muhiww,9xl,a5b7s8,14npcwi,1bkfw1s,4ys,14lipw4,kalr6k,0,1aq,kalqzg,0,48m,2j6hqf,zik0zk,0,33mcjk,0,5' // ;)
var splitted = magicString.split`,`;
var binarySequence = splitted.map(function(piece) {
return ('0'.repeat(32) + // 000000000... this will be padded
parseInt(a,36) // parseInt('190zcw0',36) -> 000000002722627584
.toString(2) // -> 10100010010010000000000000000000
).substr(-32) // left pad binary sequence
}).join``; // create one big binary sequence from several smaller
var groupsOfThree = binarySequence.match(/.{1,3}/g);
return groupsOfThree.map(function(three) {
return ` .:\`|;'\n`[parseInt(a,2)]; // magic.. turn 010 into : etc
}).join``; // create them blaze
}
function printTimeLeft() {
// this is way longer than it should be.. probably
var minimumTimeDifference = Math.min(
dateDiff('/4/20'), // -> Difference between now and 2016/4/20 00:00:00
dateDiff(' 4:20'), // 2016 04:20:00.. Sadly the 2016 is needed (i think)
dateDiff(' 0:4:20'), // 2016 00:04:20
dateDiff(' 16:20'), // Damn 12 hour clock :(
dateDiff(' 0:16:20'),
dateDiff(` ${dateString[1]} // 2016 Apr
${dateString[2]+1} // 2016 Apr 13 (12+1)
0:4:20` // Check the first occurrence of 4 minutes and 20 seconds
// the next day
)
var timeInSeconds = minimumTimeDifference / 1000;
return Math.floor(timeInSeconds) + // ~~ works like Math.floor
` minutes and ${Math.floor(timeInSeconds%60)} seconds left until your next hit.`;
}
시도 해봐!
f=
_=>(a=(d=Date)(c=new d(),z=O=>Math.abs(new d(a[3]+O)-c)).split` `)[1]=='Apr'&a[2]==20|~a[4].search(/(04|16):20/)?'0,0,2ca2o,0,10e,0,0,1eu9z4,0,22w,1ulajuo,0,bklxc,2zgg,i,120gdfk,8lc,1s1s,15,j0jf9c,7em8,tac,10,190zcw0,tm8w,ksk,hra0ia,mihog0,3aels,wy,iv8e15,b98u80,cvs1s,575,9fm71g,190zcw0,bg7vgg,1t4,148d4lu,121pblx,b9ea68,2b36,iv8hn5,9zleso,15kytz4,98cp,4fwpwk,zir9ud,1h9u3ln,11c6vb4,84kda8,kbuo05,b98u84,14possy,k9su6i,a26hwk,zvft34,kavrpc,1tn1j4,1r3jis,kamgao,a5bhq8,2b2q,beyt6x,j0y810,muhiww,9xl,a5b7s8,14npcwi,1bkfw1s,4ys,14lipw4,kalr6k,0,1aq,kalqzg,0,48m,2j6hqf,zik0zk,0,33mcjk,0,5'.split`,`.map(a=>('0'.repeat(32)+parseInt(a,36).toString(2)).substr(-32)).join``.match(/.{1,3}/g).map(a=>` .:\`|;'
`[parseInt(a,2)]).join``:~~((T=Math.min(z('/4/20'),z(` ${a[1]} ${++a[2]} 0:4:20`),z(' 4:20'),z(' 0:4:20'),z(' 16:20'),z(' 0:16:20'))/1000)/60)+` minutes and ${~~(T%60)} seconds left until your next hit.`
alert(f())
다음 코드 스 니펫에서 아스키 아트를 테스트 할 날짜를 설정할 수 있습니다
day=prompt('Day?', 12);
month=prompt('Month?', 'Apr');
f=
_=>(a=(d=Date)(c=new d(),z=O=>Math.abs(new d(a[3]+O)-c)).split` `)[1]==month&a[2]==day|~a[4].search(/(04|16):20/)?'0,0,2ca2o,0,10e,0,0,1eu9z4,0,22w,1ulajuo,0,bklxc,2zgg,i,120gdfk,8lc,1s1s,15,j0jf9c,7em8,tac,10,190zcw0,tm8w,ksk,hra0ia,mihog0,3aels,wy,iv8e15,b98u80,cvs1s,575,9fm71g,190zcw0,bg7vgg,1t4,148d4lu,121pblx,b9ea68,2b36,iv8hn5,9zleso,15kytz4,98cp,4fwpwk,zir9ud,1h9u3ln,11c6vb4,84kda8,kbuo05,b98u84,14possy,k9su6i,a26hwk,zvft34,kavrpc,1tn1j4,1r3jis,kamgao,a5bhq8,2b2q,beyt6x,j0y810,muhiww,9xl,a5b7s8,14npcwi,1bkfw1s,4ys,14lipw4,kalr6k,0,1aq,kalqzg,0,48m,2j6hqf,zik0zk,0,33mcjk,0,5'.split`,`.map(a=>('0'.repeat(32)+parseInt(a,36).toString(2)).substr(-32)).join``.match(/.{1,3}/g).map(a=>` .:\`|;'
`[parseInt(a,2)]).join``:~~((T=Math.min(z('/4/20'),z(` ${a[1]} ${++a[2]} 0:4:20`),z(' 4:20'),z(' 0:4:20'),z(' 16:20'),z(' 0:16:20'))/1000)/60)+` minutes and ${~~(T%60)} seconds left until your next hit.`
alert(f())