나는 실제로 다소 같은 일을하고 있지만 AWS S3 스토리지에서 :-
업로드 된 파일을 수신하는 서블릿에 대한 코드 :-
import java.io.IOException;
import java.io.PrintWriter;
import java.util.List;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
import com.src.code.s3.S3FileUploader;
public class FileUploadHandler extends HttpServlet {
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
doPost(request, response);
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
PrintWriter out = response.getWriter();
try{
List<FileItem> multipartfiledata = new ServletFileUpload(new DiskFileItemFactory()).parseRequest(request);
S3FileUploader s3 = new S3FileUploader();
String result = s3.fileUploader(multipartfiledata);
out.print(result);
} catch(Exception e){
System.out.println(e.getMessage());
}
}
}
이 데이터를 AWS 객체로 업로드하는 코드 :-
import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.util.List;
import java.util.UUID;
import org.apache.commons.fileupload.FileItem;
import com.amazonaws.AmazonClientException;
import com.amazonaws.AmazonServiceException;
import com.amazonaws.auth.ClasspathPropertiesFileCredentialsProvider;
import com.amazonaws.services.s3.AmazonS3;
import com.amazonaws.services.s3.AmazonS3Client;
import com.amazonaws.services.s3.model.ObjectMetadata;
import com.amazonaws.services.s3.model.PutObjectRequest;
import com.amazonaws.services.s3.model.S3Object;
public class S3FileUploader {
private static String bucketName = "***NAME OF YOUR BUCKET***";
private static String keyName = "Object-"+UUID.randomUUID();
public String fileUploader(List<FileItem> fileData) throws IOException {
AmazonS3 s3 = new AmazonS3Client(new ClasspathPropertiesFileCredentialsProvider());
String result = "Upload unsuccessfull because ";
try {
S3Object s3Object = new S3Object();
ObjectMetadata omd = new ObjectMetadata();
omd.setContentType(fileData.get(0).getContentType());
omd.setContentLength(fileData.get(0).getSize());
omd.setHeader("filename", fileData.get(0).getName());
ByteArrayInputStream bis = new ByteArrayInputStream(fileData.get(0).get());
s3Object.setObjectContent(bis);
s3.putObject(new PutObjectRequest(bucketName, keyName, bis, omd));
s3Object.close();
result = "Uploaded Successfully.";
} catch (AmazonServiceException ase) {
System.out.println("Caught an AmazonServiceException, which means your request made it to Amazon S3, but was "
+ "rejected with an error response for some reason.");
System.out.println("Error Message: " + ase.getMessage());
System.out.println("HTTP Status Code: " + ase.getStatusCode());
System.out.println("AWS Error Code: " + ase.getErrorCode());
System.out.println("Error Type: " + ase.getErrorType());
System.out.println("Request ID: " + ase.getRequestId());
result = result + ase.getMessage();
} catch (AmazonClientException ace) {
System.out.println("Caught an AmazonClientException, which means the client encountered an internal error while "
+ "trying to communicate with S3, such as not being able to access the network.");
result = result + ace.getMessage();
}catch (Exception e) {
result = result + e.getMessage();
}
return result;
}
}
참고 :-자격 증명에 aws 속성 파일을 사용하고 있습니다.
도움이 되었기를 바랍니다.