답변:
물론이지.
$ dd if=/dev/sda of=mbr bs=512 count=1
1+0 records in
1+0 records out
512 bytes (512 B) copied, 0.000188571 s, 2.7 MB/s
$ stat -c %s mbr
512
$ hd mbr
00000000 eb 48 90 d0 bc 00 7c 8e c0 8e d8 be 00 7c bf 00 |.H....|......|..|
00000010 06 b9 00 02 fc f3 a4 50 68 1c 06 cb fb b9 04 00 |.......Ph.......|
00000020 bd be 07 80 7e 00 00 7c 0b 0f 85 10 01 83 c5 10 |....~..|........|
00000030 e2 f1 cd 18 88 56 00 55 c6 46 11 05 c6 46 03 02 |.....V.U.F...F..|
00000040 ff 00 00 20 01 00 00 00 00 02 fa 90 90 f6 c2 80 |... ............|
00000050 75 02 b2 80 ea 59 7c 00 00 31 c0 8e d8 8e d0 bc |u....Y|..1......|
00000060 00 20 fb a0 40 7c 3c ff 74 02 88 c2 52 be 7f 7d |. ..@|<.t...R..}|
00000070 e8 34 01 f6 c2 80 74 54 b4 41 bb aa 55 cd 13 5a |.4....tT.A..U..Z|
00000080 52 72 49 81 fb 55 aa 75 43 a0 41 7c 84 c0 75 05 |RrI..U.uC.A|..u.|
00000090 83 e1 01 74 37 66 8b 4c 10 be 05 7c c6 44 ff 01 |...t7f.L...|.D..|
000000a0 66 8b 1e 44 7c c7 04 10 00 c7 44 02 01 00 66 89 |f..D|.....D...f.|
000000b0 5c 08 c7 44 06 00 70 66 31 c0 89 44 04 66 89 44 |\..D..pf1..D.f.D|
000000c0 0c b4 42 cd 13 72 05 bb 00 70 eb 7d b4 08 cd 13 |..B..r...p.}....|
000000d0 73 0a f6 c2 80 0f 84 ea 00 e9 8d 00 be 05 7c c6 |s.............|.|
000000e0 44 ff 00 66 31 c0 88 f0 40 66 89 44 04 31 d2 88 |D..f1...@f.D.1..|
000000f0 ca c1 e2 02 88 e8 88 f4 40 89 44 08 31 c0 88 d0 |........@.D.1...|
00000100 c0 e8 02 66 89 04 66 a1 44 7c 66 31 d2 66 f7 34 |...f..f.D|f1.f.4|
00000110 88 54 0a 66 31 d2 66 f7 74 04 88 54 0b 89 44 0c |.T.f1.f.t..T..D.|
00000120 3b 44 08 7d 3c 8a 54 0d c0 e2 06 8a 4c 0a fe c1 |;D.}<.T.....L...|
00000130 08 d1 8a 6c 0c 5a 8a 74 0b bb 00 70 8e c3 31 db |...l.Z.t...p..1.|
00000140 b8 01 02 cd 13 72 2a 8c c3 8e 06 48 7c 60 1e b9 |.....r*....H|`..|
00000150 00 01 8e db 31 f6 31 ff fc f3 a5 1f 61 ff 26 42 |....1.1.....a.&B|
00000160 7c be 85 7d e8 40 00 eb 0e be 8a 7d e8 38 00 eb ||..}.@.....}.8..|
00000170 06 be 94 7d e8 30 00 be 99 7d e8 2a 00 eb fe 47 |...}.0...}.*...G|
00000180 52 55 42 20 00 47 65 6f 6d 00 48 61 72 64 20 44 |RUB .Geom.Hard D|
00000190 69 73 6b 00 52 65 61 64 00 20 45 72 72 6f 72 00 |isk.Read. Error.|
000001a0 bb 01 00 b4 0e cd 10 ac 3c 00 75 f4 c3 00 00 00 |........<.u.....|
000001b0 00 00 00 00 00 00 00 00 29 b6 ef 39 00 00 00 00 |........)..9....|
000001c0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................|
000001d0 01 6f 83 fe bf f6 af 35 1b 00 88 d8 9e 00 00 fe |.o.....5........|
000001e0 ff ff 0f fe ff ff 2a 32 a2 01 97 58 ff 10 00 00 |......*2...X....|
000001f0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 55 aa |..............U.|
00000200
이것이 어떻게 작동하는지 man dd 와 man hd 를 참조하십시오 .
그리고 그래 dd에주의하십시오! 남용하지 마십시오 sudo
. 그룹 disk
멤버십이있는 일반 사용자 계정 은 블록을 읽기에 충분합니다. "권한이 거부되었습니다"라고 표시되면 — 하드 드라이브를 덮어 쓰려고 할 수 있습니다. 수행중인 작업을 자세히 살펴보십시오. MBR이 지워지면 파티션 테이블이 손실됩니다. 복구하기는 어렵습니다 (불가능하지는 않지만). :주의 깊게 하드 드라이브 장치를 시계 /dev/sda
와 혼동하지 마십시오 /dev/sda1
나 /dev/sdb
. 조심하고 서두르지 마십시오. 읽어보십시오 man dd
. 행운을 빕니다.
제안 된 답변 외에도 간단하게 사용하는 것이 좋습니다 hd
.
sudo hd /dev/sda -n 512 -s 0x0
00000000 eb 48 90 d7 bc 00 7a bb a0 07 8e db 8e c3 be 00 |.H....z.........|
00000010 02 8b ce fc f3 a4 ea a3 00 a0 07 b9 04 00 8b fd |................|
00000020 80 3d 80 74 05 83 c7 10 e2 f6 c3 b9 04 00 8b f5 |.=.t............|
00000030 88 2c 83 c6 10 e2 f9 c6 05 80 c3 60 b4 43 03 02 |.,.........`.C..|
00000040 ff 00 00 20 01 00 00 00 00 02 fa 90 90 f6 c2 80 |... ............|
00000050 75 02 b2 80 ea 59 7c 00 00 31 c0 8e d8 8e d0 bc |u....Y|..1......|
00000060 00 20 fb a0 40 7c 3c ff 74 02 88 c2 52 be 7f 7d |. ..@|<.t...R..}|
00000070 e8 34 01 f6 c2 80 74 54 b4 41 bb aa 55 cd 13 5a |.4....tT.A..U..Z|
00000080 52 72 49 81 fb 55 aa 75 43 a0 41 7c 84 c0 75 05 |RrI..U.uC.A|..u.|
00000090 83 e1 01 74 37 66 8b 4c 10 be 05 7c c6 44 ff 01 |...t7f.L...|.D..|
000000a0 66 8b 1e 44 7c c7 04 10 00 c7 44 02 01 00 66 89 |f..D|.....D...f.|
000000b0 5c 08 c7 44 06 00 70 66 31 c0 89 44 04 66 89 44 |\..D..pf1..D.f.D|
000000c0 0c b4 42 cd 13 72 05 bb 00 70 eb 7d b4 08 cd 13 |..B..r...p.}....|
000000d0 73 0a f6 c2 80 0f 84 ea 00 e9 8d 00 be 05 7c c6 |s.............|.|
000000e0 44 ff 00 66 31 c0 88 f0 40 66 89 44 04 31 d2 88 |D..f1...@f.D.1..|
000000f0 ca c1 e2 02 88 e8 88 f4 40 89 44 08 31 c0 88 d0 |........@.D.1...|
00000100 c0 e8 02 66 89 04 66 a1 44 7c 66 31 d2 66 f7 34 |...f..f.D|f1.f.4|
00000110 88 54 0a 66 31 d2 66 f7 74 04 88 54 0b 89 44 0c |.T.f1.f.t..T..D.|
00000120 3b 44 08 7d 3c 8a 54 0d c0 e2 06 8a 4c 0a fe c1 |;D.}<.T.....L...|
00000130 08 d1 8a 6c 0c 5a 8a 74 0b bb 00 70 8e c3 31 db |...l.Z.t...p..1.|
00000140 b8 01 02 cd 13 72 2a 8c c3 8e 06 48 7c 60 1e b9 |.....r*....H|`..|
00000150 00 01 8e db 31 f6 31 ff fc f3 a5 1f 61 ff 26 42 |....1.1.....a.&B|
00000160 7c be 85 7d e8 40 00 eb 0e be 8a 7d e8 38 00 eb ||..}.@.....}.8..|
00000170 06 be 94 7d e8 30 00 be 99 7d e8 2a 00 eb fe 47 |...}.0...}.*...G|
00000180 52 55 42 20 00 47 65 6f 6d 00 48 61 72 64 20 44 |RUB .Geom.Hard D|
00000190 69 73 6b 00 52 65 61 64 00 20 45 72 72 6f 72 00 |isk.Read. Error.|
000001a0 bb 01 00 b4 0e cd 10 ac 3c 00 75 f4 c3 00 00 00 |........<.u.....|
000001b0 00 00 00 00 00 00 00 00 b2 ec b2 ec 00 00 80 01 |................|
000001c0 01 00 07 fe 3f 34 3f 00 00 00 b6 fd 0c 00 00 00 |....?4?.........|
000001d0 01 35 0f ef ff ff f5 fd 0c 00 cc 39 ec 0d 00 00 |.5.........9....|
000001e0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................|
000001f0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 55 aa |..............U.|
해결책은 /dev/sda
읽을 수있는 특수 장치 파일 이라는 사실을 기반으로합니다 .